Q1) \(x + 9\over 5\) - \(x + 9\over 8\) = [ \(3 x + 27\over 40\) ]

Q1) \(6\over x+ 2\) + \(8\over x +3\) = [ \(14 x + 34\over x^{2}+ 5 x +6 \)]

Q1) \(10\over x+ 5\) + \(5\over x -2\) = [ \(15 x + 5\over x^{2}+3x -10 \)]

Q2) \(x + 9\over 3\) - \(x + 6\over 5\) = [ \(2 x + 27\over 15\) ]

Q2) \(9\over x+ 5\) - \(4\over x +2\) = [ \(5 x -2\over x^{2}+ 7 x +10 \)]

Q2) \(7\over x+ 5\) + \(9\over x +6\) = [ \(16 x + 87\over x^{2}+11x +30 \)]

Q3) \(x + 10\over 2\) + \(x + 7\over 2\) = [ \(2 x + 17\over 2\) ]

Q3) \(10\over x+ 7\) - \(6\over x +5\) = [ \(4 x + 8\over x^{2}+ 12 x +35 \)]

Q3) \(10\over x+ 4\) - \(4\over x -5\) = [ \(6 x -66\over x^{2}-x -20 \)]

Q4) \(x + 5\over 3\) - \(x + 8\over 5\) = [ \(2 x + 1\over 15\) ]

Q4) \(10\over x+ 6\) - \(7\over x +6\) = [ \(3 x + 18\over x^{2}+ 12 x +36 \)]

Q4) \(9\over x+ 5\) - \(2\over x -3\) = [ \(7 x -37\over x^{2}+2x -15 \)]

Q5) \(x + 10\over 3\) - \(x + 8\over 5\) = [ \(2 x + 26\over 15\) ]

Q5) \(8\over x+ 2\) + \(4\over x +3\) = [ \(12 x + 32\over x^{2}+ 5 x +6 \)]

Q5) \(10\over x+ 9\) + \(6\over x -3\) = [ \(16 x + 24\over x^{2}+6x -27 \)]

Q6) \(x + 10\over 3\) + \(x + 3\over 2\) = [ \(5 x + 29\over 6\) ]

Q6) \(9\over x+ 7\) + \(9\over x +7\) = [ \(18 x + 126\over x^{2}+ 14 x +49 \)]

Q6) \(8\over x+ 4\) - \(6\over x -10\) = [ \(2 x -104\over x^{2}-6x -40 \)]

Q7) \(x + 10\over 8\) + \(x + 9\over 7\) = [ \(15 x + 142\over 56\) ]

Q7) \(8\over x+ 2\) - \(6\over x +5\) = [ \(2 x + 28\over x^{2}+ 7 x +10 \)]

Q7) \(9\over x+ 7\) - \(2\over x -3\) = [ \(7 x -41\over x^{2}+4x -21 \)]

Q8) \(x + 9\over 2\) - \(x + 10\over 9\) = [ \(7 x + 61\over 18\) ]

Q8) \(8\over x+ 5\) + \(8\over x +2\) = [ \(16 x + 56\over x^{2}+ 7 x +10 \)]

Q8) \(8\over x+ 2\) + \(10\over x -9\) = [ \(18 x -52\over x^{2}-7x -18 \)]

Q9) \(x + 10\over 3\) + \(x + 4\over 3\) = [ \(2 x + 14\over 3\) ]

Q9) \(7\over x+ 5\) + \(10\over x +7\) = [ \(17 x + 99\over x^{2}+ 12 x +35 \)]

Q9) \(6\over x+ 4\) - \(3\over x -5\) = [ \(3 x -42\over x^{2}-x -20 \)]

Q10) \(x + 7\over 3\) - \(x + 7\over 5\) = [ \(2 x + 14\over 15\) ]

Q10) \(9\over x+ 3\) - \(5\over x +3\) = [ \(4 x + 12\over x^{2}+ 6 x +9 \)]

Q10) \(6\over x+ 3\) + \(5\over x -4\) = [ \(11x -9\over x^{2}-x -12 \)]