Q1) \(x + 4\over 3\) + \(x + 10\over 4\) = [ \(7 x + 46\over 12\) ]

Q1) \(5\over x+ 3\) + \(4\over x +3\) = [ \(9 x + 27\over x^{2}+ 6 x +9 \)]

Q1) \(8\over x+ 3\) - \(4\over x -9\) = [ \(4 x -84\over x^{2}-6x -27 \)]

Q2) \(x + 6\over 4\) + \(x + 8\over 5\) = [ \(9 x + 62\over 20\) ]

Q2) \(10\over x+ 5\) + \(6\over x +4\) = [ \(16 x + 70\over x^{2}+ 9 x +20 \)]

Q2) \(10\over x+ 7\) - \(5\over x +2\) = [ \(5 x -15\over x^{2}+9x +14 \)]

Q3) \(x + 6\over 3\) - \(x + 6\over 5\) = [ \(2 x + 12\over 15\) ]

Q3) \(9\over x+ 4\) - \(5\over x +3\) = [ \(4 x + 7\over x^{2}+ 7 x +12 \)]

Q3) \(8\over x+ 3\) - \(5\over x +2\) = [ \(3 x + 1\over x^{2}+5x +6 \)]

Q4) \(x + 8\over 4\) + \(x + 5\over 2\) = [ \(3 x + 18\over 4\) ]

Q4) \(9\over x+ 2\) + \(9\over x +7\) = [ \(18 x + 81\over x^{2}+ 9 x +14 \)]

Q4) \(9\over x+ 7\) - \(5\over x -2\) = [ \(4 x -53\over x^{2}+5x -14 \)]

Q5) \(x + 10\over 2\) - \(x + 9\over 7\) = [ \(5 x + 52\over 14\) ]

Q5) \(9\over x+ 7\) + \(6\over x +2\) = [ \(15 x + 60\over x^{2}+ 9 x +14 \)]

Q5) \(10\over x+ 6\) - \(6\over x +4\) = [ \(4 x + 4\over x^{2}+10x +24 \)]

Q6) \(x + 9\over 6\) + \(x + 10\over 7\) = [ \(13 x + 123\over 42\) ]

Q6) \(10\over x+ 7\) + \(8\over x +6\) = [ \(18 x + 116\over x^{2}+ 13 x +42 \)]

Q6) \(8\over x+ 2\) + \(6\over x -7\) = [ \(14 x -44\over x^{2}-5x -14 \)]

Q7) \(x + 4\over 2\) + \(x + 8\over 7\) = [ \(9 x + 44\over 14\) ]

Q7) \(10\over x+ 5\) - \(8\over x +4\) = [ \(2 x\over x^{2}+ 9 x +20 \)]

Q7) \(9\over x+ 3\) - \(6\over x -5\) = [ \(3 x -63\over x^{2}-2x -15 \)]

Q8) \(x + 6\over 5\) - \(x + 9\over 8\) = [ \(3 x + 3\over 40\) ]

Q8) \(8\over x+ 6\) - \(5\over x +2\) = [ \(3 x -14\over x^{2}+ 8 x +12 \)]

Q8) \(8\over x+ 3\) - \(4\over x -10\) = [ \(4 x -92\over x^{2}-7x -30 \)]

Q9) \(x + 6\over 2\) + \(x + 9\over 2\) = [ \(2 x + 15\over 2\) ]

Q9) \(6\over x+ 2\) - \(3\over x +2\) = [ \(3 x + 6\over x^{2}+ 4 x +4 \)]

Q9) \(7\over x+ 4\) + \(4\over x -6\) = [ \(11x -26\over x^{2}-2x -24 \)]

Q10) \(x + 10\over 2\) - \(x + 8\over 7\) = [ \(5 x + 54\over 14\) ]

Q10) \(10\over x+ 4\) + \(8\over x +4\) = [ \(18 x + 72\over x^{2}+ 8 x +16 \)]

Q10) \(9\over x+ 4\) + \(5\over x -8\) = [ \(14 x -52\over x^{2}-4x -32 \)]