Q1) \(x + 7\over 3\) + \(x + 9\over 8\) = [ \(11x + 83\over 24\) ]

Q1) \(9\over x+ 2\) + \(7\over x +6\) = [ \(16 x + 68\over x^{2}+ 8 x +12 \)]

Q1) \(6\over x+ 5\) + \(8\over x -2\) = [ \(14 x + 28\over x^{2}+3x -10 \)]

Q2) \(x + 6\over 2\) - \(x + 6\over 5\) = [ \(3 x + 18\over 10\) ]

Q2) \(10\over x+ 4\) - \(8\over x +4\) = [ \(2 x + 8\over x^{2}+ 8 x +16 \)]

Q2) \(10\over x+ 2\) - \(3\over x -2\) = [ \(7 x -26\over x^{2} -4 \)]

Q3) \(x + 7\over 2\) + \(x + 4\over 2\) = [ \(2 x + 11\over 2\) ]

Q3) \(3\over x+ 2\) + \(9\over x +3\) = [ \(12 x + 27\over x^{2}+ 5 x +6 \)]

Q3) \(10\over x+ 7\) - \(6\over x +2\) = [ \(4 x -22\over x^{2}+9x +14 \)]

Q4) \(x + 5\over 3\) - \(x + 6\over 5\) = [ \(2 x + 7\over 15\) ]

Q4) \(10\over x+ 3\) - \(6\over x +3\) = [ \(4 x + 12\over x^{2}+ 6 x +9 \)]

Q4) \(4\over x+ 2\) + \(3\over x +2\) = [ \(7 x + 14\over x^{2}+4x +4 \)]

Q5) \(x + 9\over 3\) + \(x + 3\over 2\) = [ \(5 x + 27\over 6\) ]

Q5) \(7\over x+ 3\) + \(10\over x +8\) = [ \(17 x + 86\over x^{2}+ 11x +24 \)]

Q5) \(8\over x+ 5\) - \(5\over x -8\) = [ \(3 x -89\over x^{2}-3x -40 \)]

Q6) \(x + 9\over 3\) - \(x + 10\over 7\) = [ \(4 x + 33\over 21\) ]

Q6) \(8\over x+ 6\) + \(9\over x +5\) = [ \(17 x + 94\over x^{2}+ 11x +30 \)]

Q6) \(9\over x+ 4\) + \(3\over x -4\) = [ \(12 x -24\over x^{2} -16 \)]

Q7) \(x + 8\over 3\) + \(x + 10\over 7\) = [ \(10 x + 86\over 21\) ]

Q7) \(10\over x+ 7\) - \(6\over x +3\) = [ \(4 x -12\over x^{2}+ 10 x +21 \)]

Q7) \(10\over x+ 4\) - \(2\over x -3\) = [ \(8 x -38\over x^{2}+x -12 \)]

Q8) \(x + 8\over 5\) - \(x + 10\over 9\) = [ \(4 x + 22\over 45\) ]

Q8) \(9\over x+ 7\) - \(4\over x +3\) = [ \(5 x -1\over x^{2}+ 10 x +21 \)]

Q8) \(10\over x+ 5\) - \(4\over x -9\) = [ \(6 x -110\over x^{2}-4x -45 \)]

Q9) \(x + 8\over 4\) - \(x + 8\over 7\) = [ \(3 x + 24\over 28\) ]

Q9) \(3\over x+ 2\) + \(10\over x +7\) = [ \(13 x + 41\over x^{2}+ 9 x +14 \)]

Q9) \(9\over x+ 3\) + \(10\over x +6\) = [ \(19 x + 84\over x^{2}+9x +18 \)]

Q10) \(x + 8\over 5\) + \(x + 6\over 2\) = [ \(7 x + 46\over 10\) ]

Q10) \(10\over x+ 6\) - \(6\over x +2\) = [ \(4 x -16\over x^{2}+ 8 x +12 \)]

Q10) \(10\over x+ 6\) - \(6\over x +3\) = [ \(4 x -6\over x^{2}+9x +18 \)]