Q1) \(x + 6\over 3\) ÷ \(9 \over {x + 7}\) = [ \(x^2 + 13 x + 42\over 27\) ]

Q1) \(x + 6\over 1\) x \(4 \over{ x + 7}\) = [ \(4( x + 6) \over( x + 7)\) ]

Q1) \(x + 7\over 2\) x \(x + 3\over x + 7\) = [ \(x + 3\over 2\) ]

Q2) \(x + 7\over 7\) x \(x + 2\over 4\) = [ \(x^2 + 9 x + 14\over 28\) ]

Q2) \(x + 9\over 8\) x \(7 \over{ x + 3}\) = [ \(7( x + 9) \over 8 ( x + 3)\) ]

Q2) \(x + 3\over 7\) ÷ \( x + 3\over x + 2\) = [ \(x + 2\over 7\) ]

Q3) \(x + 5\over 7\) x \(x + 3\over 10\) = [ \(x^2 + 8 x + 15\over 70\) ]

Q3) \(x + 4\over 2\) ÷ \({ x + 6} \over 5 \) = [ \(5( x + 4) \over 2 ( x + 6)\) ]

Q3) \(x + 1\over 6\) x \(x + 3\over x + 1\) = [ \(x + 3\over 6\) ]

Q4) \(x + 8\over 10\) ÷ \(6 \over {x + 6}\) = [ \(x^2 + 14 x + 48\over 60\) ]

Q4) \(x + 5\over 5\) ÷ \({ x + 4} \over 4 \) = [ \(4( x + 5) \over 5 ( x + 4)\) ]

Q4) \(x + 8\over 4\) ÷ \( x + 8\over x + 2\) = [ \(x + 2\over 4\) ]

Q5) \(x + 5\over 3\) x \(x + 3\over 6\) = [ \(x^2 + 8 x + 15\over 18\) ]

Q5) \(x + 9\over 9\) x \(7 \over{ x + 4}\) = [ \(7( x + 9) \over 9 ( x + 4)\) ]

Q5) \(x + 9\over 4\) x \(x + 1\over x + 9\) = [ \(x + 1\over 4\) ]

Q6) \(x + 4\over 10\) x \(x + 10\over 4\) = [ \(x^2 + 14 x + 40\over 40\) ]

Q6) \(x + 8\over 1\) x \(1 \over{ x + 2}\) = [ \(1( x + 8) \over( x + 2)\) ]

Q6) \(x + 4\over 7\) ÷ \( x + 4\over x + 8\) = [ \(x + 8\over 7\) ]

Q7) \(x + 6\over 2\) ÷ \(5 \over {x + 4}\) = [ \(x^2 + 10 x + 24\over 10\) ]

Q7) \(x + 7\over 7\) x \(10 \over{ x + 2}\) = [ \(10( x + 7) \over 7 ( x + 2)\) ]

Q7) \(x + 10\over 9\) x \(x + 9\over x + 10\) = [ \(x + 9\over 9\) ]

Q8) \(x + 1\over 6\) ÷ \(3 \over {x + 5}\) = [ \(x^2 + 6 x + 5\over 18\) ]

Q8) \(x + 2\over 9\) x \(10 \over{ x + 3}\) = [ \(10( x + 2) \over 9 ( x + 3)\) ]

Q8) \(x + 5\over 9\) ÷ \( x + 5\over x + 4\) = [ \(x + 4\over 9\) ]

Q9) \(x + 10\over 7\) ÷ \(7 \over {x + 10}\) = [ \(x^2 + 20 x + 100\over 49\) ]

Q9) \(x + 3\over 1\) x \(1 \over{ x + 2}\) = [ \(1( x + 3) \over( x + 2)\) ]

Q9) \(x + 7\over 9\) x \(x + 2\over x + 7\) = [ \(x + 2\over 9\) ]

Q10) \(x + 1\over 3\) x \(x + 1\over 2\) = [ \(x^2 + 2 x + 1\over 6\) ]

Q10) \(x + 9\over 8\) x \(3 \over{ x + 1}\) = [ \(3( x + 9) \over 8 ( x + 1)\) ]

Q10) \(x + 1\over 9\) ÷ \( x + 1\over x + 3\) = [ \(x + 3\over 9\) ]