Q1) \(x + 8\over 2\) ÷ \(10 \over {x + 5}\) = [ \(x^2 + 13 x + 40\over 20\) ]

Q1) \(x + 5\over 2\) ÷ \({ x + 1} \over 7 \) = [ \(7( x + 5) \over 2 ( x + 1)\) ]

Q1) \(x + 2\over 9\) ÷ \( x + 2\over x + 1\) = [ \(x + 1\over 9\) ]

Q2) \(x + 3\over 6\) ÷ \(7 \over {x + 6}\) = [ \(x^2 + 9 x + 18\over 42\) ]

Q2) \(x + 3\over 1\) ÷ \({ x + 2} \over 1 \) = [ \(1( x + 3) \over( x + 2)\) ]

Q2) \(x + 8\over 10\) ÷ \( x + 8\over x + 4\) = [ \(x + 4\over 10\) ]

Q3) \(x + 8\over 10\) x \(x + 7\over 8\) = [ \(x^2 + 15 x + 56\over 80\) ]

Q3) \(x + 1\over 2\) ÷ \({ x + 5} \over 5 \) = [ \(5( x + 1) \over 2 ( x + 5)\) ]

Q3) \(x + 3\over 6\) x \(x + 9\over x + 3\) = [ \(x + 9\over 6\) ]

Q4) \(x + 9\over 8\) ÷ \(2 \over {x + 3}\) = [ \(x^2 + 12 x + 27\over 16\) ]

Q4) \(x + 10\over 10\) x \(7 \over{ x + 7}\) = [ \(7( x + 10) \over 10 ( x + 7)\) ]

Q4) \(x + 2\over 7\) x \(x + 9\over x + 2\) = [ \(x + 9\over 7\) ]

Q5) \(x + 3\over 10\) ÷ \(8 \over {x + 10}\) = [ \(x^2 + 13 x + 30\over 80\) ]

Q5) \(x + 4\over 5\) x \(4 \over{ x + 9}\) = [ \(4( x + 4) \over 5 ( x + 9)\) ]

Q5) \(x + 5\over 7\) ÷ \( x + 5\over x + 9\) = [ \(x + 9\over 7\) ]

Q6) \(x + 9\over 5\) x \(x + 4\over 4\) = [ \(x^2 + 13 x + 36\over 20\) ]

Q6) \(x + 1\over 4\) x \(1 \over{ x + 6}\) = [ \(1( x + 1) \over 4 ( x + 6)\) ]

Q6) \(x + 6\over 5\) x \(x + 2\over x + 6\) = [ \(x + 2\over 5\) ]

Q7) \(x + 4\over 9\) x \(x + 8\over 8\) = [ \(x^2 + 12 x + 32\over 72\) ]

Q7) \(x + 7\over 10\) ÷ \({ x + 3} \over 7 \) = [ \(7( x + 7) \over 10 ( x + 3)\) ]

Q7) \(x + 10\over 10\) ÷ \( x + 10\over x + 1\) = [ \(x + 1\over 10\) ]

Q8) \(x + 8\over 2\) ÷ \(6 \over {x + 8}\) = [ \(x^2 + 16 x + 64\over 12\) ]

Q8) \(x + 2\over 5\) ÷ \({ x + 5} \over 1 \) = [ \(1( x + 2) \over 5 ( x + 5)\) ]

Q8) \(x + 6\over 8\) ÷ \( x + 6\over x + 2\) = [ \(x + 2\over 8\) ]

Q9) \(x + 5\over 3\) ÷ \(4 \over {x + 7}\) = [ \(x^2 + 12 x + 35\over 12\) ]

Q9) \(x + 7\over 5\) x \(3 \over{ x + 1}\) = [ \(3( x + 7) \over 5 ( x + 1)\) ]

Q9) \(x + 2\over 10\) ÷ \( x + 2\over x + 10\) = [ \(x + 10\over 10\) ]

Q10) \(x + 3\over 4\) x \(x + 7\over 2\) = [ \(x^2 + 10 x + 21\over 8\) ]

Q10) \(x + 3\over 2\) ÷ \({ x + 1} \over 5 \) = [ \(5( x + 3) \over 2 ( x + 1)\) ]

Q10) \(x + 3\over 6\) x \(x + 7\over x + 3\) = [ \(x + 7\over 6\) ]