Q1) \(x + 10\over 9\) x \(x + 1\over 2\) = [ \(x^2 + 11x + 10\over 18\) ]

Q1) \(x + 7\over 3\) ÷ \({ x + 1} \over 2 \) = [ \(2( x + 7) \over 3 ( x + 1)\) ]

Q1) \(x + 6\over 7\) x \(x + 9\over x + 6\) = [ \(x + 9\over 7\) ]

Q2) \(x + 9\over 9\) ÷ \(6 \over {x + 10}\) = [ \(x^2 + 19 x + 90\over 54\) ]

Q2) \(x + 9\over 2\) ÷ \({ x + 2} \over 3 \) = [ \(3( x + 9) \over 2 ( x + 2)\) ]

Q2) \(x + 7\over 6\) ÷ \( x + 7\over x + 6\) = [ \(x + 6\over 6\) ]

Q3) \(x + 10\over 5\) x \(x + 6\over 6\) = [ \(x^2 + 16 x + 60\over 30\) ]

Q3) \(x + 7\over 3\) ÷ \({ x + 2} \over 1 \) = [ \(1( x + 7) \over 3 ( x + 2)\) ]

Q3) \(x + 8\over 10\) ÷ \( x + 8\over x + 6\) = [ \(x + 6\over 10\) ]

Q4) \(x + 2\over 10\) ÷ \(9 \over {x + 6}\) = [ \(x^2 + 8 x + 12\over 90\) ]

Q4) \(x + 4\over 8\) x \(3 \over{ x + 10}\) = [ \(3( x + 4) \over 8 ( x + 10)\) ]

Q4) \(x + 5\over 10\) ÷ \( x + 5\over x + 6\) = [ \(x + 6\over 10\) ]

Q5) \(x + 9\over 8\) ÷ \(3 \over {x + 4}\) = [ \(x^2 + 13 x + 36\over 24\) ]

Q5) \(x + 8\over 5\) ÷ \({ x + 1} \over 2 \) = [ \(2( x + 8) \over 5 ( x + 1)\) ]

Q5) \(x + 8\over 8\) x \(x + 7\over x + 8\) = [ \(x + 7\over 8\) ]

Q6) \(x + 4\over 2\) ÷ \(8 \over {x + 3}\) = [ \(x^2 + 7 x + 12\over 16\) ]

Q6) \(x + 1\over 3\) ÷ \({ x + 7} \over 10 \) = [ \(10( x + 1) \over 3 ( x + 7)\) ]

Q6) \(x + 3\over 2\) ÷ \( x + 3\over x + 5\) = [ \(x + 5\over 2\) ]

Q7) \(x + 8\over 2\) ÷ \(7 \over {x + 7}\) = [ \(x^2 + 15 x + 56\over 14\) ]

Q7) \(x + 1\over 9\) x \(8 \over{ x + 9}\) = [ \(8( x + 1) \over 9 ( x + 9)\) ]

Q7) \(x + 10\over 7\) ÷ \( x + 10\over x + 4\) = [ \(x + 4\over 7\) ]

Q8) \(x + 7\over 8\) ÷ \(10 \over {x + 6}\) = [ \(x^2 + 13 x + 42\over 80\) ]

Q8) \(x + 2\over 5\) x \(4 \over{ x + 4}\) = [ \(4( x + 2) \over 5 ( x + 4)\) ]

Q8) \(x + 4\over 2\) x \(x + 7\over x + 4\) = [ \(x + 7\over 2\) ]

Q9) \(x + 5\over 10\) ÷ \(10 \over {x + 5}\) = [ \(x^2 + 10 x + 25\over 100\) ]

Q9) \(x + 4\over 3\) x \(4 \over{ x + 3}\) = [ \(4( x + 4) \over 3 ( x + 3)\) ]

Q9) \(x + 2\over 2\) ÷ \( x + 2\over x + 1\) = [ \(x + 1\over 2\) ]

Q10) \(x + 1\over 5\) ÷ \(2 \over {x + 8}\) = [ \(x^2 + 9 x + 8\over 10\) ]

Q10) \(x + 1\over 1\) x \(3 \over{ x + 4}\) = [ \(3( x + 1) \over( x + 4)\) ]

Q10) \(x + 4\over 3\) ÷ \( x + 4\over x + 7\) = [ \(x + 7\over 3\) ]