Mr Daniels Maths
Conversions: Mixed to Improper fractions

Set 1

Set 2

Set 3

Q1) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q1) 6\(\frac{1}{6}\)= [ \(37\over6\) ]

Q1) 8\(\frac{10}{11}\)= [ \(98\over11\) ]

Q2) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q2) 6\(\frac{1}{5}\)= [ \(31\over5\) ]

Q2) 11\(\frac{1}{12}\)= [ \(133\over12\) ]

Q3) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q3) 10\(\frac{5}{6}\)= [ \(65\over6\) ]

Q3) 4\(\frac{5}{11}\)= [ \(49\over11\) ]

Q4) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q4) 6\(\frac{5}{6}\)= [ \(41\over6\) ]

Q4) 7\(\frac{7}{11}\)= [ \(84\over11\) ]

Q5) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q5) 5\(\frac{1}{5}\)= [ \(26\over5\) ]

Q5) 9\(\frac{5}{8}\)= [ \(77\over8\) ]

Q6) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q6) 5\(\frac{5}{6}\)= [ \(35\over6\) ]

Q6) 3\(\frac{2}{11}\)= [ \(35\over11\) ]

Q7) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q7) 11\(\frac{2}{5}\)= [ \(57\over5\) ]

Q7) 11\(\frac{5}{11}\)= [ \(126\over11\) ]

Q8) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q8) 10\(\frac{1}{5}\)= [ \(51\over5\) ]

Q8) 7\(\frac{7}{12}\)= [ \(91\over12\) ]

Q9) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q9) 10\(\frac{4}{5}\)= [ \(54\over5\) ]

Q9) 16\(\frac{5}{8}\)= [ \(133\over8\) ]

Q10) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q10) 10\(\frac{1}{6}\)= [ \(61\over6\) ]

Q10) 3\(\frac{8}{9}\)= [ \(35\over9\) ]