Mr Daniels Maths
Conversions: Mixed to Improper fractions

Set 1

Set 2

Set 3

Q1) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q1) 6\(\frac{1}{6}\)= [ \(37\over6\) ]

Q1) 8\(\frac{10}{11}\)= [ \(98\over11\) ]

Q2) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q2) 8\(\frac{1}{6}\)= [ \(49\over6\) ]

Q2) 4\(\frac{3}{8}\)= [ \(35\over8\) ]

Q3) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q3) 11\(\frac{1}{6}\)= [ \(67\over6\) ]

Q3) 9\(\frac{11}{12}\)= [ \(119\over12\) ]

Q4) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q4) 6\(\frac{4}{5}\)= [ \(34\over5\) ]

Q4) 12\(\frac{4}{9}\)= [ \(112\over9\) ]

Q5) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q5) 5\(\frac{1}{5}\)= [ \(26\over5\) ]

Q5) 5\(\frac{1}{11}\)= [ \(56\over11\) ]

Q6) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q6) 9\(\frac{1}{6}\)= [ \(55\over6\) ]

Q6) 6\(\frac{2}{9}\)= [ \(56\over9\) ]

Q7) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q7) 11\(\frac{1}{5}\)= [ \(56\over5\) ]

Q7) 10\(\frac{9}{11}\)= [ \(119\over11\) ]

Q8) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q8) 4\(\frac{3}{5}\)= [ \(23\over5\) ]

Q8) 6\(\frac{3}{10}\)= [ \(63\over10\) ]

Q9) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q9) 4\(\frac{1}{6}\)= [ \(25\over6\) ]

Q9) 14\(\frac{7}{9}\)= [ \(133\over9\) ]

Q10) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q10) 12\(\frac{2}{5}\)= [ \(62\over5\) ]

Q10) 4\(\frac{1}{12}\)= [ \(49\over12\) ]