Mr Daniels Maths
Factorising Double Brackets 2

Set 1

Set 2

Set 3

Q1) Factorise \(x^2 -5x -14\). [ \((x + 2)(x -7)\)]

Q1) Factorise the following;
\(x^2 -25 =\) [ \((x + 5)(x -5)\)]

Q1) Factorise the following;
\(4 x^2 + 12 x+ 9= \)
[ \((2x + 3)(2x + 3)\)]

Q2) Factorise \(x^2 -5x -24\). [ \((x + 3)(x -8)\)]

Q2) Factorise the following;
\(100x^2 -16 =\) [ \((10x -4)(10x + 4)\)]

Q2) Factorise the following;
\(9 x^2 + 6 x+ 1= \)
[ \((3x + 1)(3x + 1)\)]

Q3) Factorise \(x^2 -2x -35\). [ \((x + 5)(x -7)\)]

Q3) Factorise the following;
\(x^2 -9 =\) [ \((x + 3)(x -3)\)]

Q3) Factorise the following;
\(6 x^2 + 7 x+ 2= \)
[ \((2x + 1)(3x + 2)\)]

Q4) Factorise \(x^2 + x -12\). [ \((x + 4)(x -3)\)]

Q4) Factorise the following;
\(100x^2 -81 =\) [ \((10x + 9)(10x -9)\)]

Q4) Factorise the following;
\(6 x^2 + 5 x+ 1= \)
[ \((3x + 1)(2x + 1)\)]

Q5) Factorise \(x^2 + 4x -32\). [ \((x + 8)(x -4)\)]

Q5) Factorise the following;
\(64x^2 -121 =\) [ \((8x + 11)(8x -11)\)]

Q5) Factorise the following;
\(9 x^2 + 15 x+ 4= \)
[ \((3x + 1)(3x + 4)\)]

Q6) Factorise \(x^2 -8x -20\). [ \((x + 2)(x -10)\)]

Q6) Factorise the following;
\(16x^2 -64 =\) [ \((4x -8)(4x + 8)\)]

Q6) Factorise the following;
\(8 x^2 + 14 x+ 3= \)
[ \((4x + 1)(2x + 3)\)]

Q7) Factorise \(x^2 -2x -8\). [ \((x + 2)(x -4)\)]

Q7) Factorise the following;
\(x^2 -64 =\) [ \((x + 8)(x -8)\)]

Q7) Factorise the following;
\(8 x^2 + 14 x+ 5= \)
[ \((2x + 1)(4x + 5)\)]

Q8) Factorise \(x^2 + 3x -10\). [ \((x + 5)(x -2)\)]

Q8) Factorise the following;
\(x^2 -49 =\) [ \((x + 7)(x -7)\)]

Q8) Factorise the following;
\(8 x^2 + 10 x+ 3= \)
[ \((2x + 1)(4x + 3)\)]

Q9) Factorise \(x^2 -6x -16\). [ \((x + 2)(x -8)\)]

Q9) Factorise the following;
\(x^2 -36 =\) [ \((x + 6)(x -6)\)]

Q9) Factorise the following;
\(4 x^2 + 8 x+ 3= \)
[ \((2x + 3)(2x + 1)\)]

Q10) Factorise \(x^2 + 2x -8\). [ \((x + 4)(x -2)\)]

Q10) Factorise the following;
\(25x^2 -16 =\) [ \((5x -4)(5x + 4)\)]

Q10) Factorise the following;
\(6 x^2 + 17 x+ 5= \)
[ \((2x + 5)(3x + 1)\)]