Mr Daniels Maths
Functions Inverse

Set 1

Set 2

Set 3

Q1) \(g(x) =3{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over3\)]

Q1) f(x) = \(x\over 3\) + 4. Find f'(x). [ \(f'(x) \)= \(3(x -4)\)]

Q1) g(x) =\(x^ 2 + 8\). Find g'(x). [ g'(x)= \( \sqrt[2]{x -8} \)]

Q2) g(x) =x + 10. Find g'(x). [ g'(x) = x -10]

Q2) f(x) = \(x\over 7\) + 9. Find f'(x). [ \(f'(x) \)= \(7(x -9)\)]

Q2) h(x) =\( 2 x^ 3 + 4\). Find h'(x). [ h'(x)= \( \sqrt[3]{{x -4}\over 2} \)]

Q3) \(g(x) =4{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over4\)]

Q3) g(x) = \(x\over 5\) + 3. Find g'(x). [ \(g'(x) \)= \(5(x -3)\)]

Q3) g(x) =\( 6 x^ 2 + 10\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x -10}\over 6} \)]

Q4) h(x) =x -8. Find h'(x). [ h'(x) = x +8]

Q4) f(x) = 6 x + 10. Find f'(x). [ \(f'(x) \)= \({x -10}\over6\)]

Q4) f(x) =\( 6 x^ 2 -10\). Find f'(x). [ f'(x)= \( \sqrt[2]{{x +10}\over 6} \)]

Q5) g(x) =x + 5. Find g'(x). [ g'(x) = x -5]

Q5) f(x) = 7 x + 6. Find f'(x). [ \(f'(x) \)= \({x -6}\over7\)]

Q5) f(x) =\( 7 x^ 2 + 5\). Find f'(x). [ f'(x)= \( \sqrt[2]{{x -5}\over 7} \)]

Q6) \(f(x) =3{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over3\)]

Q6) f(x) = \(x\over 10\) + 2. Find f'(x). [ \(f'(x) \)= \(10(x -2)\)]

Q6) g(x) =\( 10 x^ 2 -5\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x +5}\over 10} \)]

Q7) \(h(x) =8{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over8\)]

Q7) g(x) = \(x\over 9\) -6. Find g'(x). [ \(g'(x) \)= \(9(x +6)\)]

Q7) h(x) =\( 2 x^ 3 -5\). Find h'(x). [ h'(x)= \( \sqrt[3]{{x +5}\over 2} \)]

Q8) \(f(x) =9{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over9\)]

Q8) f(x) = 9 x + 6. Find f'(x). [ \(f'(x) \)= \({x -6}\over9\)]

Q8) h(x) =\(x^ 3 -10\). Find h'(x). [ h'(x)= \( \sqrt[3]{x +10} \)]

Q9) g(x) =x + 10. Find g'(x). [ g'(x) = x -10]

Q9) g(x) = 4 x -7. Find g'(x). [ \(g'(x) \)= \({x +7}\over4\)]

Q9) h(x) =\(x^ 2 + 6\). Find h'(x). [ h'(x)= \( \sqrt[2]{x -6} \)]

Q10) \(h(x) =9{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over9\)]

Q10) h(x) = 7 x + 2. Find h'(x). [ \(h'(x) \)= \({x -2}\over7\)]

Q10) h(x) =\( 9 x^ 3 -6\). Find h'(x). [ h'(x)= \( \sqrt[3]{{x +6}\over 9} \)]