Mr Daniels Maths
Mixed Numbers 4 Operations

Set 1

Set 2

Set 3

Q1) 1\(\frac{4}{5}\) + 2\(\frac{1}{2}\) = [ 4\(\frac{3}{10}\)]

Q1) 3\(\frac{2}{3}\) - 1\(\frac{3}{8}\) = [ 2\(\frac{7}{24}\)]

Q1) 1\(\frac{4}{5}\) \(\div\) 2\(\frac{2}{3}\) = [ \(\frac{27}{40}\)]

Q2) 1\(\frac{1}{7}\) + 3\(\frac{1}{3}\) = [ 4\(\frac{10}{21}\)]

Q2) 2\(\frac{1}{2}\) - 2\(\frac{1}{7}\) = [ \(\frac{5}{14}\)]

Q2) 1\(\frac{1}{8}\) \(\div\) 1\(\frac{1}{2}\) = [ \(\frac{3}{4}\)]

Q3) 1\(\frac{3}{5}\) + 1\(\frac{3}{5}\) = [ 3\(\frac{1}{5}\)]

Q3) 3\(\frac{2}{3}\) - 1\(\frac{5}{12}\) = [ 2\(\frac{1}{4}\)]

Q3) 1\(\frac{1}{2}\) \(\div\) 1\(\frac{1}{2}\) = [ 1]

Q4) 2\(\frac{1}{2}\) + 2\(\frac{1}{2}\) = [ 5]

Q4) 2\(\frac{2}{3}\) - 2\(\frac{3}{7}\) = [ \(\frac{5}{21}\)]

Q4) 1\(\frac{1}{3}\) x 3\(\frac{1}{3}\) = [ 4\(\frac{4}{9}\)]

Q5) 1\(\frac{1}{9}\) + 1\(\frac{1}{2}\) = [ 2\(\frac{11}{18}\)]

Q5) 2\(\frac{1}{4}\) - 1\(\frac{6}{7}\) = [ \(\frac{11}{28}\)]

Q5) 1\(\frac{1}{3}\) \(\div\) 3\(\frac{1}{2}\) = [ \(\frac{8}{21}\)]

Q6) 1\(\frac{4}{5}\) + 1\(\frac{3}{7}\) = [ 3\(\frac{8}{35}\)]

Q6) 1\(\frac{7}{9}\) - 1\(\frac{2}{5}\) = [ \(\frac{17}{45}\)]

Q6) 1\(\frac{3}{5}\) x 1\(\frac{4}{5}\) = [ 2\(\frac{22}{25}\)]

Q7) 2\(\frac{2}{3}\) + 1\(\frac{2}{5}\) = [ 4\(\frac{1}{15}\)]

Q7) 2\(\frac{1}{2}\) - 1\(\frac{5}{9}\) = [ \(\frac{17}{18}\)]

Q7) 1\(\frac{1}{5}\) x 1\(\frac{3}{4}\) = [ 2\(\frac{1}{10}\)]

Q8) 2\(\frac{1}{4}\) + 1\(\frac{1}{2}\) = [ 3\(\frac{3}{4}\)]

Q8) 3\(\frac{1}{2}\) - 1\(\frac{7}{8}\) = [ 1\(\frac{5}{8}\)]

Q8) 1\(\frac{2}{3}\) \(\div\) 1\(\frac{1}{8}\) = [ 1\(\frac{13}{27}\)]

Q9) 1\(\frac{3}{5}\) + 1\(\frac{1}{3}\) = [ 2\(\frac{14}{15}\)]

Q9) 1\(\frac{4}{7}\) - 1\(\frac{3}{7}\) = [ \(\frac{1}{7}\)]

Q9) 2\(\frac{1}{3}\) x 2\(\frac{2}{3}\) = [ 6\(\frac{2}{9}\)]

Q10) 2\(\frac{1}{2}\) + 1\(\frac{1}{4}\) = [ 3\(\frac{3}{4}\)]

Q10) 3\(\frac{1}{2}\) - 2\(\frac{1}{4}\) = [ 1\(\frac{1}{4}\)]

Q10) 1\(\frac{1}{7}\) \(\div\) 2\(\frac{1}{2}\) = [ \(\frac{16}{35}\)]