Mr Daniels Maths
Solving Equations with Brackets

Set 1

Set 2

Set 3

Q1) \(2(x + 2) = 14\) [ x= \(5\)]

Q1) 2(2x -4) = 12 [ x = 5]

Q1) 2(9y -9) = 18 [ y = 2]

Q2) \(8(z + 7) = 128\) [ z= \(9\)]

Q2) 6(5z -3) = 72 [ z = 3]

Q2) 5(3w -8) = 35 [ w = 5]

Q3) \(4(x -6) = 4\) [ x= \(7\)]

Q3) 3(9y + 5) = 69 [ y = 2]

Q3) 3(5w + 2) = 81 [ w = 5]

Q4) \(8(w -4) = 32\) [ w= \(8\)]

Q4) 2(7z + 2) = 32 [ z = 2]

Q4) 3(2x -5) = 21 [ x = 6]

Q5) \(3(x + 3) = 30\) [ x= \(7\)]

Q5) 2(3x -4) = 34 [ x = 7]

Q5) 19(3x -10) = 95 [ x = 5]

Q6) \(2(y -3) = 6\) [ y= \(6\)]

Q6) 2(4z + 7) = 94 [ z = 10]

Q6) 2(2y + 9) = 50 [ y = 8]

Q7) \(10(w + 6) = 80\) [ w= \(2\)]

Q7) 3(4y + 10) = 66 [ y = 3]

Q7) 4(9x + 2) = 80 [ x = 2]

Q8) \(7(y -2) = 7\) [ y= \(3\)]

Q8) 3(8y + 8) = 72 [ y = 2]

Q8) 3(2y + 10) = 60 [ y = 5]

Q9) \(5(x -6) = 10\) [ x= \(8\)]

Q9) 5(4z -7) = 45 [ z = 4]

Q9) 2(2z + 10) = 44 [ z = 6]

Q10) \(6(z + 8) = 72\) [ z= \(4\)]

Q10) 9(3x -9) = 27 [ x = 4]

Q10) 18(2z -10) = -108 [ z = 2]