Mr Daniels Maths
Solving Equations 3 Brackets

Set 1

Set 2

Set 3

Q1) \( {z\over3}+3 = 6\) [ \(z= 9\)]

Q1) \(10(y + 4) = 120\) [ y= \(8\)]

Q1) 8(2z -2) = 80 [ z = 6]

Q2) \( {w\over4}-8 = 2\) [ \(w= 40\)]

Q2) \(8(x + 8) = 128\) [ x= \(8\)]

Q2) 2(5x + 9) = 58 [ x = 4]

Q3) \(6y -6 = 48\) [ \( y = 9\)]

Q3) \(6(w -3) = 24\) [ w= \(7\)]

Q3) 5(5w -9) = 55 [ w = 4]

Q4) \(12x + 9 = 45\) [ \( x = 3\)]

Q4) \(6(w + 9) = 72\) [ w= \(3\)]

Q4) 5(2x + 2) = 40 [ x = 3]

Q5) \(11z -8 = 25\) [ \( z = 3\)]

Q5) \(5(y -2) = 5\) [ y= \(3\)]

Q5) 3(10z + 8) = 84 [ z = 2]

Q6) \( {y\over7}+10 = 14\) [ \(y= 28\)]

Q6) \(9(y -2) = 72\) [ y= \(10\)]

Q6) 2(3w -7) = 22 [ w = 6]

Q7) \(11z -5 = 72\) [ \( z = 7\)]

Q7) \(5(y + 2) = 20\) [ y= \(2\)]

Q7) 6(8x -3) = 78 [ x = 2]

Q8) \(14y + 5 = 89\) [ \( y = 6\)]

Q8) \(7(x + 9) = 133\) [ x= \(10\)]

Q8) 7(3y -8) = -14 [ y = 2]

Q9) \(3w -3 = 24\) [ \( w = 9\)]

Q9) \(9(x -5) = 27\) [ x= \(8\)]

Q9) 3(3x + 5) = 60 [ x = 5]

Q10) \( {x\over7}+7 = 9\) [ \(x= 14\)]

Q10) \(2(x + 6) = 24\) [ x= \(6\)]

Q10) 4(4w -5) = 28 [ w = 3]