Mr Daniels Maths
Surds:Division

Set 1

Set 2

Set 3

Q1) \(\sqrt 32 \over{ \sqrt{ 4}} \) = [ \(2\sqrt{2}\)]

Q1) \(4 \sqrt 14 \over{ \sqrt 7} \) = [ \(4\sqrt{2}\)]

Q1) \(10 \sqrt 8 \over{ 2 \sqrt 4} \) = [ \(5\sqrt{2}\)]

Q2) \(\sqrt 60 \over{ \sqrt{ 10}} \) = [ \(\sqrt{6}\)]

Q2) \(4 \sqrt 20 \over{ \sqrt 4} \) = [ \(4\sqrt{5}\)]

Q2) \(6 \sqrt 10 \over{ 2 \sqrt 5} \) = [ \(3\sqrt{2}\)]

Q3) \(\sqrt 42 \over{ \sqrt{ 6}} \) = [ \(\sqrt{7}\)]

Q3) \(4 \sqrt 20 \over{ \sqrt 2} \) = [ \(4\sqrt{10}\)]

Q3) \(6 \sqrt 25 \over{ 2 \sqrt 5} \) = [ \(3\sqrt{5}\)]

Q4) \(\sqrt 9 \over{ \sqrt{ 3}} \) = [ \(\sqrt{3}\)]

Q4) \(4 \sqrt 2 \over{ \sqrt 1} \) = [ \(4\sqrt{2}\)]

Q4) \(12 \sqrt 9 \over{ 4 \sqrt 3} \) = [ \(3\sqrt{3}\)]

Q5) \(\sqrt 30 \over{ \sqrt{ 5}} \) = [ \(\sqrt{6}\)]

Q5) \(2 \sqrt 16 \over{ \sqrt 4} \) = [ \(4\)]

Q5) \(6 \sqrt 10 \over{ 3 \sqrt 2} \) = [ \(2\sqrt{5}\)]

Q6) \(\sqrt 60 \over{ \sqrt{ 6}} \) = [ \(\sqrt{10}\)]

Q6) \(5 \sqrt 18 \over{ \sqrt 9} \) = [ \(5\sqrt{2}\)]

Q6) \(8 \sqrt 9 \over{ 2 \sqrt 3} \) = [ \(4\sqrt{3}\)]

Q7) \(\sqrt 45 \over{ \sqrt{ 9}} \) = [ \(\sqrt{5}\)]

Q7) \(2 \sqrt 2 \over{ \sqrt 2} \) = [ \(2\)]

Q7) \(15 \sqrt 10 \over{ 3 \sqrt 2} \) = [ \(5\sqrt{5}\)]

Q8) \(\sqrt 50 \over{ \sqrt{ 10}} \) = [ \(\sqrt{5}\)]

Q8) \(4 \sqrt 6 \over{ \sqrt 3} \) = [ \(4\sqrt{2}\)]

Q8) \(25 \sqrt 25 \over{ 5 \sqrt 5} \) = [ \(5\sqrt{5}\)]

Q9) \(\sqrt 56 \over{ \sqrt{ 8}} \) = [ \(\sqrt{7}\)]

Q9) \(3 \sqrt 20 \over{ \sqrt 5} \) = [ \(6\)]

Q9) \(10 \sqrt 20 \over{ 2 \sqrt 5} \) = [ \(10\)]

Q10) \(\sqrt 25 \over{ \sqrt{ 5}} \) = [ \(\sqrt{5}\)]

Q10) \(2 \sqrt 18 \over{ \sqrt 2} \) = [ \(6\)]

Q10) \(12 \sqrt 12 \over{ 4 \sqrt 3} \) = [ \(6\)]