Mr Daniels Maths
Surds Simplifying

Set 1

Set 2

Set 3

Q1) \(\sqrt{20}\) = [ \(2\sqrt{5}\)]

Q1) \(3\sqrt 7 \) x \(4\sqrt 2= \) [ \(12\sqrt{14}\)]

Q1) \(\sqrt { 108 } \) + \(\sqrt { 48 }= \) [ \(10\sqrt{3}\)]

Q2) \(\sqrt{288}\) = [ \(12\sqrt{2}\)]

Q2) \(15 \sqrt 28 \over{ 5 \sqrt 7} \) = [ \(6\)]

Q2) \(\sqrt { 500 } \) + \(\sqrt { 20 }= \) [ \(12\sqrt{5}\)]

Q3) \(\sqrt{32}\) = [ \(4\sqrt{2}\)]

Q3) \(20 \sqrt 24 \over{ 4 \sqrt 8} \) = [ \(5\sqrt{3}\)]

Q3) \(\sqrt { 128 } \) + \(\sqrt { 98 }= \) [ \(15\sqrt{2}\)]

Q4) \(\sqrt{12}\) = [ \(2\sqrt{3}\)]

Q4) \(2\sqrt 5 \) x \(4\sqrt 10= \) [ \(40\sqrt{2}\)]

Q4) \(\sqrt { 405 } \) + \(\sqrt { 500 }= \) [ \(19\sqrt{5}\)]

Q5) \(\sqrt{125}\) = [ \(5\sqrt{5}\)]

Q5) \(5\sqrt 3 \) x \(4\sqrt 7= \) [ \(20\sqrt{21}\)]

Q5) \(\sqrt { 48 } \) - \(\sqrt { 12 }= \) [ \(2\sqrt{3}\)]

Q6) \(\sqrt{28}\) = [ \(2\sqrt{7}\)]

Q6) \(4 \sqrt 25 \over{ 2 \sqrt 5} \) = [ \(2\sqrt{5}\)]

Q6) \(\sqrt { 128 } \) - \(\sqrt { 98 }= \) [ \(\sqrt{2}\)]

Q7) \(\sqrt{18}\) = [ \(3\sqrt{2}\)]

Q7) \(2\sqrt 4 \) x \(2\sqrt 4= \) [ \(16\)]

Q7) \(\sqrt { 20 } \) - \(\sqrt { 5 }= \) [ \(\sqrt{5}\)]

Q8) \(\sqrt{252}\) = [ \(6\sqrt{7}\)]

Q8) \(8 \sqrt 63 \over{ 2 \sqrt 7} \) = [ \(12\)]

Q8) \(\sqrt { 27 } \) + \(\sqrt { 27 }= \) [ \(6\sqrt{3}\)]

Q9) \(\sqrt{80}\) = [ \(4\sqrt{5}\)]

Q9) \(9 \sqrt 90 \over{ 3 \sqrt 9} \) = [ \(3\sqrt{10}\)]

Q9) \(\sqrt { 245 } \) - \(\sqrt { 5 }= \) [ \(6\sqrt{5}\)]

Q10) \(\sqrt{48}\) = [ \(4\sqrt{3}\)]

Q10) \(3\sqrt 4 \) x \(5\sqrt 9= \) [ \(90\)]

Q10) \(\sqrt { 162 } \) - \(\sqrt { 18 }= \) [ \(6\sqrt{2}\)]